-2x^2+20x-128=0

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Solution for -2x^2+20x-128=0 equation: 



-2x^2+20x-128=0

a = -2; b = 20; c = -128;
Δ = b2-4ac
Δ = 202-4·(-2)·(-128)
Δ = -624
Delta is less than zero, so there is no solution for the equation

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